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0.2x^2-19.6x+602.2=622
We move all terms to the left:
0.2x^2-19.6x+602.2-(622)=0
We add all the numbers together, and all the variables
0.2x^2-19.6x-19.8=0
a = 0.2; b = -19.6; c = -19.8;
Δ = b2-4ac
Δ = -19.62-4·0.2·(-19.8)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19.6)-20}{2*0.2}=\frac{-0.4}{0.4} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19.6)+20}{2*0.2}=\frac{39.6}{0.4} =99 $
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